Patrick B. answered • 09/29/20

Math and computer tutor/teacher

X+y = 10000

0.07x + 0.06y = 610

0.07x + 0.06 ( 10000 - x) = 610

0.07x + 600 - 0.06x = 610

0.01x + 600 = 610

0.01x = 10

x = 1000

y =9000

Sophie A.

asked • 09/28/20Last year, Dan had 10000 to invest. He invested some of it in an account that paid 7% simple interest per year, and he invested the rest in an account that paid 6% simple interest per year. After one year, he received a total of $610 in interest. How much did he invest in each account?

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Patrick B. answered • 09/29/20

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(31)
Math and computer tutor/teacher

X+y = 10000

0.07x + 0.06y = 610

0.07x + 0.06 ( 10000 - x) = 610

0.07x + 600 - 0.06x = 610

0.01x + 600 = 610

0.01x = 10

x = 1000

y =9000

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